[C23] Handle type compatibility for enumerations better (#150282)

An enumeration is compatible with its underlying type, which means that
code like the following should be accepted:

  struct A { int h; };
  void func() {
    extern struct A x;
    enum E : int { e };
    struct A { enum E h; };
    extern struct A x;
  }

because the structures are declared in different scopes, the two
declarations of 'x' are both compatible.

Note, the structural equivalence checker does not take scope into
account, but that is something the C standard requires. This means we
are accepting code we should be rejecting per the standard, like:

  void func() {
    struct A { int h; };
    extern struct A x;
    enum E : int { e };
    struct A { enum E h; };
    extern struct A x;
  }

Because the structures are declared in the same scope, the type
compatibility rule require the structures to use the same types, not
merely compatible ones.

Fixes #149965

(cherry picked from commit 315e2e28b13285a352d409b739ba31fb453d661b)
This commit is contained in:
Aaron Ballman 2025-07-29 08:20:59 -04:00 committed by Tobias Hieta
parent 6df1a2879a
commit 3b53c84e33
2 changed files with 59 additions and 1 deletions

View File

@ -873,7 +873,29 @@ static bool IsStructurallyEquivalent(StructuralEquivalenceContext &Context,
else if (T1->getTypeClass() == Type::FunctionNoProto &&
T2->getTypeClass() == Type::FunctionProto)
TC = Type::FunctionNoProto;
else
else if (Context.LangOpts.C23 && !Context.StrictTypeSpelling &&
(T1->getTypeClass() == Type::Enum ||
T2->getTypeClass() == Type::Enum)) {
// In C23, if not being strict about token equivalence, we need to handle
// the case where one type is an enumeration and the other type is an
// integral type.
//
// C23 6.7.3.3p16: The enumerated type is compatible with the underlying
// type of the enumeration.
//
// Treat the enumeration as its underlying type and use the builtin type
// class comparison.
if (T1->getTypeClass() == Type::Enum) {
T1 = T1->getAs<EnumType>()->getDecl()->getIntegerType();
if (!T2->isBuiltinType() || T1.isNull()) // Sanity check
return false;
} else if (T2->getTypeClass() == Type::Enum) {
T2 = T2->getAs<EnumType>()->getDecl()->getIntegerType();
if (!T1->isBuiltinType() || T2.isNull()) // Sanity check
return false;
}
TC = Type::Builtin;
} else
return false;
}

View File

@ -401,3 +401,39 @@ _Static_assert(0 == _Generic(inner_anon_tagged.untagged, struct { int i; } : 1,
// unions and structures are both RecordDecl objects, whereas EnumDecl is not).
enum { E_Untagged1 } nontag_enum; // both-note {{previous definition is here}}
_Static_assert(0 == _Generic(nontag_enum, enum { E_Untagged1 } : 1, default : 0)); // both-error {{redefinition of enumerator 'E_Untagged1'}}
// Test that enumerations are compatible with their underlying type, but still
// diagnose when "same type" is required rather than merely "compatible type".
enum E1 : int { e1 }; // Fixed underlying type
enum E2 { e2 }; // Unfixed underlying type, defaults to int or unsigned int
struct GH149965_1 { int h; };
// This typeof trick is used to get the underlying type of the enumeration in a
// platform agnostic way.
struct GH149965_2 { __typeof__(+(enum E2){}) h; };
void gh149965(void) {
extern struct GH149965_1 x1; // c17-note {{previous declaration is here}}
extern struct GH149965_2 x2; // c17-note {{previous declaration is here}}
// Both the structure and the variable declarations are fine because only a
// compatible type is required, not the same type, because the structures are
// declared in different scopes.
struct GH149965_1 { enum E1 h; };
struct GH149965_2 { enum E2 h; };
extern struct GH149965_1 x1; // c17-error {{redeclaration of 'x1'}}
extern struct GH149965_2 x2; // c17-error {{redeclaration of 'x2'}}
// However, in the same scope, the same type is required, not just compatible
// types.
// FIXME: this should be an error in both C17 and C23 mode.
struct GH149965_3 { int h; }; // c17-note {{previous definition is here}}
struct GH149965_3 { enum E1 h; }; // c17-error {{redefinition of 'GH149965_3'}}
// For Clang, the composite type after declaration merging is the enumeration
// type rather than an integer type.
enum E1 *eptr;
[[maybe_unused]] __typeof__(x1.h) *ptr = eptr;
enum E2 *eptr2;
[[maybe_unused]] __typeof__(x2.h) *ptr2 = eptr2;
}