Current implementation will rename both register in store instructions if
we store base address into memory with same base register, it's OK if
the offset is 0, however that is wrong transform if offset isn't 0, give
a smalle example here:
sd a0, 808(a0)
We should not transform into:
addi a2, a0, 768
sd a2, 40(a2)
That should just rename base address like this:
addi a2, a0, 768
sd a0, 40(a2)
Reviewed By: asb
Differential Revision: https://reviews.llvm.org/D128876
When optimizing for size, this pass searches for instructions that are
prevented from being compressed by one of the following:
1. The use of a single uncompressed register.
2. A base register + offset where the offset is too large to be
compressed and the base register may or may not already be compressed.
In the first case, if there is a compressed register available, then the
uncompressed register is copied to the compressed register and its uses
replaced. This is only done if there are enough uses that code size
would be improved.
In the second case, if a compressed register is available, then the
original base register is copied and adjusted such that:
new_base_register = base_register + adjustment
base_register + large_offset = new_base_register + small_offset
and the uses of the base register are replaced with the new base
register. Again this is only done if there are enough uses for code size
to be improved.
This pass was authored by Lewis Revill, with large offset optimization
added by Craig Blackmore.
Differential Revision: https://reviews.llvm.org/D92105
