If C1 is 1 and we're working with a power of two divisor, this will end up replacing the `and` for the remainder with a multiply and a longer dependency chain. Fixes https://github.com/llvm/llvm-project/issues/147176.
If C1 is 1 and we're working with a power of two divisor, this will end up replacing the `and` for the remainder with a multiply and a longer dependency chain. Fixes https://github.com/llvm/llvm-project/issues/147176.