Chris Lattner 4d1bb94c3e New testcase, allow folding of binary operators that use PHI nodes, as long
as the result of the binary operator is always constant.  This does not require
the PHI itself to be constant though.

llvm-svn: 10762
2004-01-12 03:57:00 +00:00

24 lines
479 B
LLVM

; RUN: llvm-as < %s | opt -sccp -dce -simplifycfg | llvm-dis | not grep br
int %test(int %param) {
entry:
%tmp.1 = setne int %param, 0
br bool %tmp.1, label %endif.0, label %else
else:
br label %endif.0
endif.0:
%a.0 = phi int [ 2, %else ], [ 3, %entry ]
%b.0 = phi int [ 3, %else ], [ 2, %entry ]
%tmp.5 = add int %a.0, %b.0
%tmp.7 = setne int %tmp.5, 5
br bool %tmp.7, label %UnifiedReturnBlock, label %endif.1
endif.1:
ret int 0
UnifiedReturnBlock:
ret int 2
}