Richard Smith 034185c2f9 The 'constexpr implies const' rule for non-static member functions is gone in
C++1y, so stop adding the 'const' there. Provide a compatibility warning for
code relying on this in C++11, with a fix-it hint. Update our lazily-written
tests to add the const, except for those ones which were testing our
implementation of this rule.

llvm-svn: 179969
2013-04-21 01:08:50 +00:00

35 lines
1.2 KiB
C++

// RUN: %clang_cc1 -verify -std=c++11 %s
template<typename T> struct complex {
complex(T = T(), T = T());
void operator+=(complex);
T a, b;
};
void std_example() {
complex<double> z;
z = { 1, 2 };
z += { 1, 2 };
int a, b;
a = b = { 1 };
a = { 1 } = b; // expected-error {{initializer list cannot be used on the left hand side of operator '='}}
a = a + { 4 }; // expected-error {{initializer list cannot be used on the right hand side of operator '+'}}
a = { 3 } * { 4 }; // expected-error {{initializer list cannot be used on the left hand side of operator '*'}} \
expected-error {{initializer list cannot be used on the right hand side of operator '*'}}
}
struct S {
constexpr S(int a, int b) : a(a), b(b) {}
int a, b;
};
struct T {
constexpr int operator=(S s) const { return s.a; }
constexpr int operator+=(S s) const { return s.b; }
};
static_assert((T() = {4, 9}) == 4, "");
static_assert((T() += {4, 9}) == 9, "");
int k1 = T() = { 1, 2 } = { 3, 4 }; // expected-error {{initializer list cannot be used on the left hand side of operator '='}}
int k2 = T() = { 1, 2 } + 1; // expected-error {{initializer list cannot be used on the left hand side of operator '+'}}