82655c1514
There could be some mis-alignments when copying origins not aligned. I believe inaligned memcpy is rare so the cases do not matter too much in practice. 1) About the change at line 50 Let dst be (void*)5, then d=5, beg=4 so we need to write 3 (4+4-5) bytes from 5 to 7. 2) About the change around line 77. Let dst be (void*)5, because of lines 50-55, the bytes from 5-7 were already writen. So the aligned copy is from 8. Reviewed-by: eugenis Differential Revision: https://reviews.llvm.org/D94552
Compiler-RT ================================ This directory and its subdirectories contain source code for the compiler support routines. Compiler-RT is open source software. You may freely distribute it under the terms of the license agreement found in LICENSE.txt. ================================