
parser is looking at a declaration or an expression, use a '=' to conclude that we are parsing a declaration. This is wrong. However, our previous approach of finding a comma after the '=' is also wrong, because the ',' could be part of a template-argument-list. So, for now we're going to use the same wrong heuristic as GCC and Visual C++, because less real-world code is likely to be broken this way. I've opened PR7655 to keep track of our wrongness; note also the XFAIL'd test. Fixes <rdar://problem/8193163>. llvm-svn: 108459
11 lines
178 B
C++
11 lines
178 B
C++
// RUN: %clang_cc1 -fsyntax-only -verify %s
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struct X {
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template<typename T, typename U>
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static void f(int, int);
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};
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void f() {
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void (*ptr)(int, int) = &X::f<int, int>;
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}
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